2[d+3(d-1)]=x

Solution for 2[d+3(d-1)]=x equation:

Simplifying
2[d + 3(d + -1)] = x

Reorder the terms:
2[d + 3(-1 + d)] = x
2[d + (-1 * 3 + d * 3)] = x
2[d + (-3 + 3d)] = x

Reorder the terms:
2[-3 + d + 3d] = x

Combine like terms: d + 3d = 4d
2[-3 + 4d] = x
[-3 * 2 + 4d * 2] = x
[-6 + 8d] = x

Solving
-6 + 8d = x

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 8d = 6 + x

Combine like terms: -6 + 6 = 0
0 + 8d = 6 + x
8d = 6 + x

Divide each side by '8'.
d = 0.75 + 0.125x

Simplifying
d = 0.75 + 0.125x